you have to solve the following by finding the value of x and y. can u help please?
x+3(x+1)=2x
1+3(x-1)=4
2x-2(x+1)=5x
2(3x-1)=3(x-1)
4(y-1)+3(y+2)=5(y-4)
3y+7+3(y-1)=2(2y+6)
These are exercises in standard algebraic manipulation of equations. Basically, you (1) multiply out terms in parentheses; (2) combine "like" terms and (3) then add to, subtract from, multiply or divide both sides of the equation until you get the unknown (x or y) on one side. Here is one way to do the first of them:
x+3(x+1)=2x
(Multiply out the parentheses)
x + 3x + 3 = 2x
(Combine terms in x)
4x + 3 = 2x
(Subract 2x +3 from both sides)
2x = -3
(Divide both sides by 2)
x = -3/2
Now you try the others. If cannot follow these steps, you should consider a private tutor before you fall too far behind in class.
thanx
You're welcome! I can help you solve the other equations as well. Let's go through them one by one.
1. 1 + 3(x-1) = 4
a. Distribute the 3: 1 + 3x - 3 = 4
b. Combine like terms: 3x - 2 = 4
c. Add 2 to both sides: 3x = 6
d. Divide both sides by 3: x = 2
2. 2x - 2(x+1) = 5x
a. Distribute the -2: 2x - 2x - 2 = 5x
b. Combine like terms: -2 = 5x
c. Divide both sides by 5: x = -2/5
3. 2(3x-1) = 3(x-1)
a. Distribute the 2 and 3: 6x - 2 = 3x - 3
b. Subtract 3x from both sides: 6x - 3x - 2 = -3
c. Combine like terms: 3x - 2 = -3
d. Subtract 2 from both sides: 3x = -1
e. Divide both sides by 3: x = -1/3
4. 4(y-1) + 3(y+2) = 5(y-4)
a. Distribute the 4, 3, and 5: 4y - 4 + 3y + 6 = 5y - 20
b. Combine like terms: 7y + 2 = 5y - 20
c. Subtract 5y from both sides: 7y - 5y + 2 = -20
d. Combine like terms: 2y + 2 = -20
e. Subtract 2 from both sides: 2y = -22
f. Divide both sides by 2: y = -11
5. 3y + 7 + 3(y-1) = 2(2y+6)
a. Distribute the 3 and 2: 3y + 7 + 3y - 3 = 4y + 12
b. Combine like terms: 6y + 4 = 4y + 12
c. Subtract 4y from both sides: 6y - 4y + 4 = 12
d. Combine like terms: 2y + 4 = 12
e. Subtract 4 from both sides: 2y = 8
f. Divide both sides by 2: y = 4
I hope this helps! Let me know if you have any more questions.