If a student needs an average of 70 or more to pass a course. She has scored 90, 76, and 66 on the first three exams. writing an inequality representing the score she must get on the last test to pass the course

letting x be for the exam that's missing.

on the left side write: 90+76+66+x divided by 4 then do the symbol the greater than or equal and for the right side write out : 70 divided by 4

so now you should have:
90+76+66+x greater than or equal to 280

then add the test scores

232+x greater than or equal to 280

then subtract 232 from both sides to get x alone

x greater than or equal to 48

therefore he needs 48 to get a 70 average in the class to pass to check:

add all the test scores and divide them for how many they are. so

90+76+66+48 = 280 then 280 divided by 4 = 70

good work.

Great job! You've correctly set up the inequality and solved for the missing test score. The inequality you wrote is:

90 + 76 + 66 + x ≥ 280

To find the missing test score, you need to isolate x. Here's the step-by-step process:

1. Combine the known test scores:
90 + 76 + 66 = 232

2. Substitute the combined test scores:
232 + x ≥ 280

3. Subtract 232 from both sides to isolate x:
x ≥ 280 - 232
x ≥ 48

So, she needs to score 48 or more on the last test to pass the course with an average of 70 or more.

To double-check, you can add up all the test scores and divide by the number of exams to calculate the average:
90 + 76 + 66 + 48 = 280
280 / 4 = 70

Well done on solving the problem and confirming the solution!