Posted by **Sissy** on Sunday, April 22, 2007 at 12:53am.

what would the dimensions of a retangle be whose perimeter is 50(P=50)inches when the length is 2x-5 ane the width is unknown

The width must be 25 - (2x-5) = 30-2x, since the sum of the length and width must be half the perimeter.

You do not have enough information to solve for x, or a specific length and width.

I beleive I have figured this one out:

2x+2(2x-5)=50

2x being twice the width

2(2x-5) being twice the length

and 50 being the perimeter

2x=2(2x-5)=50

2x+4x-10=50

6x-10 =50

6x=60

x=10 If you place 10 whwre the x is you get 50 as a result

If the width is x then you are correct. You had only stated that the length is 2x-5, and had not defined x. Your first line should have been

2x + 2x(2x-5) = 50

The rest is fine. The width is 10 and the length is 15

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