# algebra

posted by
**ken**
.

I have been working this one for awhile and have become more confused. Please assist.

Problem:

Find two consecutive odd integers such that 5 times the first interger is 12 more than 3 times the second.

The key thing is to realize that odd numbers, just like the even numbers, are 2 apart

So if you let the first odd number be x, then the second odd number is x+2

Now all you do is translate the English into math.

"...such that 5 times the first interger is 12 more than 3 times the second."

5x > 3(x+2) by 12

so we add 12 to the smaller side to make it into an equation.

5x = 3(x+2) + 12

easy to solve