We did a lab for acid-base titrations, and I'm having trouble with my post lab questions because I had trouble with acid-base reactions and titrations in the first place!
"Calculate the molar amounts of NaOH used in the reaction with the HCl solution and with the HC2H3O2.
I need some direction as to where I need to start and what I need to do.
Thanks!!
In a titration, mols acid = mols base.
mol = M x L.
That's all there is to it.
To calculate the molar amounts of NaOH used in the reaction with the HCl solution and HC2H3O2, you will need to follow these steps:
1. Determine the molarity of your NaOH solution. This information is typically provided in the lab.
2. Write the balanced chemical equation for the reaction of NaOH with HCl and with HC2H3O2. This will give you the stoichiometric ratio between the acid and the base.
3. Measure or note the volume (in liters) of the NaOH solution used in each titration.
4. Convert the volume of NaOH solution used into moles. To do this, multiply the volume (in liters) by the molarity of NaOH. This will give you the number of moles of NaOH used in the reaction.
5. Use the stoichiometric ratio from the balanced chemical equation to determine the number of moles of HCl and HC2H3O2 reacted with the NaOH. Since the balanced chemical equation tells you the ratio of reactants, you can use this ratio to find the moles of HCl and HC2H3O2.
6. Finally, calculate the molar amount of NaOH used with each acid by dividing the number of moles of NaOH by the volume (in liters) of the respective acid solution used in the titration.
Always remember to keep track of units and cancel out appropriate units in your calculations to ensure accurate results.
Let me know if you have any more questions or need further clarification.