180 ml of a mixture of water and alcohol with 90% alcohol concentration is mixed with 70 ml of pure water. what is the alcohol concentration of the new mixture?
Do the following:
1) Find out how many ml of alcohol was in the first mixture. (What is 90% of 180?)
2) Take that amount and divide it by 250 ml (180ml + 70ml)
Matt
1) To find out how many ml of alcohol was in the first mixture, we need to calculate 90% of 180 ml:
90% of 180 ml = (90/100) * 180 = 0.9 * 180 = 162 ml
So, there are 162 ml of alcohol in the first mixture.
2) Now, let's calculate the alcohol concentration of the new mixture by dividing the amount of alcohol (162 ml) by the total volume of the new mixture (250 ml):
Alcohol concentration = (162 ml / 250 ml) * 100% = 0.648 * 100% = 64.8%
Therefore, the alcohol concentration of the new mixture is 64.8%.