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October 30, 2014

October 30, 2014

Posted by **Anonymous** on Saturday, April 21, 2007 at 3:11pm.

i'm guessing this is something to do with parametric equations.

if x is 2, then y=5. but how do i get dx/dt.

you have to differentiate the equation with respect to t

so xy=10

x(dy/dt) + y(dx/dt) = 0

when x=2 y = 5 and dy/dt = 3

so 2(3) + 5(dx/dt) = 0

etc. solve for dx/dt

- calculus -
**natasha**, Wednesday, February 13, 2013 at 7:33pm-6/5

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