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December 20, 2014

December 20, 2014

Posted by **jasmine20** on Friday, April 20, 2007 at 4:56pm.

factor by grouping: x^3-5x^2+2x-10

My answer: (x^2+2)(x-5) *question do i need to go further?*

Errm dats almost done exept derz one more step, as you still need to chnage the quadratic equation into 2 linear ones as a Cubic equation has 3 linear functions, What i wud suggest is factorise da quadtracitic

it depends... as Mark said, you need to factor the first binomial(x^2 + 2), and if you require an answer: use the Zero Property of Multiplication to find out x sub 1 OR x sub 2.

Hope this helps...

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