Friday

April 25, 2014

April 25, 2014

Posted by **Mike** on Friday, April 20, 2007 at 2:37pm.

I moved the first equation around to get:

y = [1- the square root of (x) ] ^2

Unfortunately, this gives me bounds from 1 to 1.

So I'm stuck with:

integral from 1-1 of [1- the square root of (x) ] ^2

I used FnInt on this equation and it returns an answer of 0.

Any help or suggestions would be greatly appreciated!

Thanks alot,

Mike

The limits of dx integration are from x=0 (the x=0 line) to x=1 (where the curve crosses the y=0 line). What you want to calculate in the integral od y dx from x=0 to x=1. That can be written

(Integral of) (1 - 2 sqrt x + x) dx

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