Friday

March 27, 2015

March 27, 2015

Posted by **Mike** on Friday, April 20, 2007 at 2:37pm.

I moved the first equation around to get:

y = [1- the square root of (x) ] ^2

Unfortunately, this gives me bounds from 1 to 1.

So I'm stuck with:

integral from 1-1 of [1- the square root of (x) ] ^2

I used FnInt on this equation and it returns an answer of 0.

Any help or suggestions would be greatly appreciated!

Thanks alot,

Mike

The limits of dx integration are from x=0 (the x=0 line) to x=1 (where the curve crosses the y=0 line). What you want to calculate in the integral od y dx from x=0 to x=1. That can be written

(Integral of) (1 - 2 sqrt x + x) dx

**Answer this Question**

**Related Questions**

Algebra - Use the quadratic formula to solve the equation. Give exact answers: ...

college pre-calculus - simplify: square root (4/3)-square root (3/4) A. 2-...

Math simplifying mixed radicals - Please help me simplify these following mixed ...

Algebra - Rationalize each expression by building perfect nth root factors for ...

algebra - 1.)correct 2.)wrong---> the first term is wrong 4(3a^2)^2 = 36a^4 3...

Math Help! - Four students worked to find an estimate for square root 22. Who is...

College Algebra - I need some help with a handful of questions. I need to see ...

College Algebra - I need some help with a handful of questions. I need to see ...

Math ~CHECK MY ANSWER~ - 1) Which of these is a rational number? a. Pi b. Square...

7th grade math Ms. Sue please - 2. Shelly sews a blanket that has an area of 170...