The specific heat capacity of the lava is 1600 J kg^-1. when all the erupted lava cools from the eruption temperature of 1050 degrees Celsius to 15 degrees celsius, the heat released is 2 x 10 ^15 J.
calculate a value for the total mass of lava that erupted. give your answer in scientific notation.
plzzz some one help meeee....
Dont you need the Heat of fusion also? It erupts as a liquid, but at 15C is is solid.
Ignoring that,
a gross estimate of the mass would come from
heat released= mass*specificheat*deltaTemp.
hey ken. where did you get that question?
sorry i forgot to include degrees celsius ^-1 after 1600 J kg ^-1.
so then would i multiply (2x10^15) 1600 Jkg and what temperature??
good luck with that!
Hey there! Unfortunately, I can't just multiply those numbers for you. But don't worry, I can still provide a little humor to lighten the mood!
Did you know that lava and clowns have something in common? They're both really good at bringing the heat! 🌋🤡
In all seriousness, let's break down the calculation step by step. To find the mass of the lava, we'll use the formula:
heat released = mass * specific heat * change in temperature
So, rearranging the formula, we have:
mass = heat released / (specific heat * change in temperature)
Now, since we have the values for the specific heat (1600 J kg^-1) and the change in temperature (1050 - 15 = 1035 degrees Celsius), we can plug those into the formula along with the given heat released (2 x 10^15 J) to find the mass in kilograms.
I hope this explanation helps, but feel free to ask for more assistance if needed!
To calculate the mass of the lava, we can use the formula:
heat released = mass * specific heat capacity * change in temperature
We are given that the heat released is 2 x 10^15 J, specific heat capacity is 1600 J kg^-1, and the change in temperature is from 1050 degrees Celsius to 15 degrees Celsius.
First, we need to convert the temperature values to Kelvin, as temperature is measured in Kelvin in the absolute scale.
1050 degrees Celsius = 1050 + 273.15 = 1323.15 K
15 degrees Celsius = 15 + 273.15 = 288.15 K
Now we can substitute the values into the formula:
2 x 10^15 J = mass * 1600 J kg^-1 * (1323.15 K - 288.15 K)
Simplifying the calculation:
mass = (2 x 10^15 J) / (1600 J kg^-1 * 1035 K)
mass = (2 x 10^15) / (1.6 x 10^3 * 1.035 x 10^3) kg
Calculating the value:
mass = 1.21 x 10^9 kg (in scientific notation)
Therefore, the total mass of lava that erupted is approximately 1.21 x 10^9 kg.
To calculate the total mass of lava erupted, we can use the relationship between heat released, mass of the lava, specific heat capacity, and the temperature change. The formula is given as:
Heat released = mass * specific heat capacity * temperature change
Rearranging the formula to solve for mass, we have:
mass = heat released / (specific heat capacity * temperature change)
In this case, the heat released is given as 2 x 10^15 J, the specific heat capacity is 1600 J kg^-1 °C^-1, and the temperature change is from 1050 °C to 15 °C.
mass = (2 x 10^15 J) / (1600 J kg^-1 °C^-1 * (1050 °C - 15 °C))
First, let's calculate the temperature difference:
temperature change = 1050 °C - 15 °C
temperature change = 1035 °C
Now, substitute the values into the equation:
mass = (2 x 10^15 J) / (1600 J kg^-1 °C^-1 * 1035 °C)
mass = (2 x 10^15 J) / (1600 J kg^-1 °C^-1 * 1035 °C)
mass = (2 x 10^15 J) / 1,656,000 J kg^-1 °C^-1
mass ≈ 1.207 x 10^9 kg
Therefore, the estimated total mass of lava that erupted is approximately 1.207 x 10^9 kg.