Wednesday

December 17, 2014

December 17, 2014

Posted by **Mary** on Wednesday, April 18, 2007 at 10:30pm.

For Further Reading

Physics HELP!!!!!!!! - bobpursley, Tuesday, April 17, 2007 at 9:29am

PV=work

V= area *distance

You know P, area, and work. Solve for distance.

According to the formula provided

PV=work

P(area x distance)= work

solve for distance

distance = work - P/ area

this is where it get confusing for me

P= 1.02 x 10^5 Pa

A= 3.06 x 10^-2 m^2

W= ? I am unsure how to get he value of work

Work is heat, and heat is work. It was given.

Please check my working out. The system is saying it is wrong.

PV = W

PV = 2109J

V = 2109J/ 1.02 X 10^5Pa

V = 0.020676471m^3

Area x distance = 0.020676471m^3

distance = 0.020676471/ 3.06 x 10^-2m^2

distance = 0.6757 m

I dont see anything wrong.

**Answer this Question**

**Related Questions**

Physics - Suppose a monatomic ideal gas is contained within a vertical cylinder ...

Physics - Suppose a monatomic ideal gas is contained within a vertical cylinder ...

Physics HELP!!!!!!!! - Suppose a monatomic ideal gas is contained within a ...

Physics HELP!!!!!!!! - Suppose a monatomic ideal gas is contained within a ...

Physics- drwls please check - Good morning. This is a repost. The system is ...

Physics repost please check - Good morning. This is a repost. The system is ...

physics - A movable piston having a mass of 8.00 kg and a cross-sectional area ...

Physics - A movable piston having a mass of 7.26 kg and a cross-sectional area ...

physics help please... - A movable piston having a mass of 8.00 kg and a cross-...

Physics - 2 moles of ideal gas are in a cylinder container with cross-sectional ...