Posted by **jamay** on Wednesday, April 18, 2007 at 7:35pm.

find the area between the x-axis and the graph of the given function over the given interval:

y = sqrt(9-x2^2) over [-3,3]

actually, it's

y = sqrt(9-x^2) over [-3,3]

## Answer This Question

## Related Questions

- calc - find the area between the x-axis and the graph of the given function over...
- Calculus - These are the two problems from my homework I don't get.. can you ...
- cal - find the area between the graph of function and x-axis over the given ...
- Math - Use the limit process to find the area of the region between the graph of...
- Calc - Use the limit process to find the area of the region between the graph of...
- Calculus - Find the equation of the tangent line to f(x)=x sec x at (pi/4, pi •...
- Functions, graphs - f(x)=(x+1)/(1+x^2) a) explain why the graph lies above the ...
- Calculus - Use the limit process to find the area of the region between the ...
- Calculus check - Given f(x)=x^4(2x^2-15). On what interval(s) is the graph of f ...
- MATH HELP - Find the volume of the solid obtained by rotating the region ...

More Related Questions