# ALGEBRA

posted by
**larry** on
.

In a town election, the winning candidate had 220 more votes

than the loser. If 810 votes were cast in all, how many votes did each candidate receive?

would the formula i need to solve this problem

x+y+220=810

y=x-220

The equations are not correct. Close, but you made a small error that would throw everything off.

You have:

x+y+220 = 810

If "x" represents one person's amount of votes and "y" equals the other person's amount of votes, you would not add ANOTHER 220 to see how many votes there were. If we said "Larry has 1 more apple than Matt and together, they have 5. How many apples does each person have?" You would not add the number I have plus the number you have plus another 5 (or we would have 10 apples since 5+5=10). Same idea here, just with bigger numbers. :)

y=x-220. Could work depending on how you define your variables. I think...haven't tried it yet and it's late here (1:15 AM)and I can't focus correctly because I'm tired. But look how I declared them below:

x = winner

y = loser

The winner (y) had 220 more votes than the loser (x) So just put that into numbers and variables as it's written:

y= 220 + x

If 810 votes were cast in all...

So if I add the number of the winner's votes and the number of the loser's votes, I have 810 votes all together:

x+y = 810

Now, you know what "y" equals (220 + x) Switch out the "y" for that and you're on your way :)

Matt