Wednesday
March 29, 2017

Post a New Question

Posted by on .

Given y=log(x), what is dy/dx?

If you have to derive this from first principles, then you have to use the defintion of the Logarithm. E.g. you could use that the Logarithm is the inverse of the exponential function and that the derivative of the exponential function is the exponential function itself.

y = Log(x) -->

x = Exp(y)

dx/dy = Exp(y) = x --->

dy/dx = 1/(dx/dy) = 1/x

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question