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April 1, 2015

April 1, 2015

Posted by **kelly** on Tuesday, April 17, 2007 at 6:03pm.

Sin(n) is always between -1 and 1. So, you have:

-1/n^2 < a(n) < 1/n^2

Both the lower bound and the upper bound converge to zero, so the sequence converges to zero.

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