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March 1, 2015

March 1, 2015

Posted by **kelly** on Tuesday, April 17, 2007 at 6:02pm.

x=3 - 2t^2 , so dx/dt = -4t

y= 5 - 2t , so dy/dt = -2

it follows that (dy/dt)÷(dx/dt)

=dy/dt

=-2/-4t

= -1/2 when t=-1

by assigning different values to t, you can generate x and y values, thus a few points.

It should be obvious quickly that your would get a parabola with vertex at (3,5), axis of symmetry y = 5, opening to the left

when t=-1, the point is (1,7) and slope =-1/2

use that information and y = mx + b to find the tangent equation

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