Monday

January 26, 2015

January 26, 2015

Posted by **kelly** on Tuesday, April 17, 2007 at 6:02pm.

x=3 - 2t^2 , so dx/dt = -4t

y= 5 - 2t , so dy/dt = -2

it follows that (dy/dt)÷(dx/dt)

=dy/dt

=-2/-4t

= -1/2 when t=-1

by assigning different values to t, you can generate x and y values, thus a few points.

It should be obvious quickly that your would get a parabola with vertex at (3,5), axis of symmetry y = 5, opening to the left

when t=-1, the point is (1,7) and slope =-1/2

use that information and y = mx + b to find the tangent equation

**Answer this Question**

**Related Questions**

Calc. - sketch the curve using the parametric equation to plot the points. use ...

Calc 3 - Find the parametric equations for the tangent line to the curve with ...

Calc 3 - Find the parametric equations for the tangent line to the curve with ...

Calculus - A curve is defined by the parametric equations: x = t2 – t and y = t3...

calc - Suppose a curve is traced by the parametric equations x=1sin(t) y=18-3cos...

calculus 2 - Express the given parametric curve by an equation in x and y, then ...

Math - Use a formula for slope of a line tangent to a parametric curve to find ...

Math - Use the formula for slope of a line tangent to a parametric curve to find...

parametric equations - On what intervals of t is the curve described by the ...

Calculus - For the parametric curve defined x=2t^3-12t^2-30t+9 and y=t^2-4t+6 .....