Posted by Hela on Tuesday, April 17, 2007 at 5:38pm.
a brown mouse is crossed with hertozygous black mouse. if the mother has a litter of four, what are thae chances all of them will be brown?
wat da hell is dat
http://en.wikipedia.org/wiki/Punnett_square
do you have more specifics? because that didn't help a bit
don't respond to my ?'s if your gonna post that bull!@#$%^&
There is a 50% chance the the litter will be brown.
Assuming that the heterozygous mouse has one recessive brown gene (b) and one dominant black gene (B) and the brown mouse is bb,
Kyonia is right
for one birth.
Thus the brown mouse can give either b or b, while the black mouse can give either b or B. Plug the symbols into the Punnett square to see how we arrrived at the conclusion.
However, the question asked for the probability that
all of them are brown. To find the probability that
all events will occur, you need to
multiply the probability of the individual events, in this case, the 4 mice. You can do the calculations.
I hope this helps. Thanks for asking.
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