Wednesday

July 23, 2014

July 23, 2014

Posted by **Evan** on Tuesday, April 17, 2007 at 4:41pm.

y=ln((4x-1)/x^3)

So far I have:

y'=(4/(4x-1))-3/x

How do I write as single fraction

let u= (4x-1) v= x^-3

dy/dx= d y/d(uv) * d(uv)/dx

dy/duv= 1/uv

d(uv)/dx= udv/dx + v du/dx

put it together.

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