March 24, 2017

Post a New Question

Posted by on Monday, April 16, 2007 at 9:28pm.

How much of solid potassium chromate whould you use to prepare 2.00 L of 0.400 M potassium chromate?

M x L = mols
g/molar mass = mols OR
M x L = g/molar mass
solve for g.

.400 mol/L x 2.00 = g/194
g = 155.2


Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question