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August 29, 2014

August 29, 2014

Posted by **Kate** on Monday, April 16, 2007 at 8:27pm.

cos^2x=3-5cosx

cos^2x + 5cosx -3=0

now you have a quadratic, solve for cos x using the equation

cosx=(-5 -+ sqrt (25 +12)/2

the back of the book says .9987+2kpi and -.09987+2kpi

when i do it i dont get that answer.

I get it, that answer is in radians. The 2kpi is to keep rotation a number of times in the circle.

Thank you so much for helping me I have AC tomorrow and without your help i would have not been able to do that whole section.

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