Monday

March 2, 2015

March 2, 2015

Posted by **Kate** on Monday, April 16, 2007 at 7:38pm.

cos^2x=3-5cosx

rewrite it as..

cos^2x + 5cosx -3=0

now you have a quadratic, solve for cos x using the equation

cosx=(-5 -+ sqrt (25 +12)/2

**Answer this Question**

**Related Questions**

trig question - Compute inverse functions to four significant digits. cos^2x=3-...

trig - it says solve for all real solutions, compute inverse functions to 4 ...

trig--power reducing formulas - Having trouble with this problem: Rewrite the ...

Math - Solving for Trig Equations - Solve the following equation for 0 less than...

Trig--check answer - Solve the equation of the interval (0, 2pi) cosx=sinx I ...

Trigonometry - Write equivalent equations in the form of inverse functions for a...

Trig - prove the identity (sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= ...

Trigonometry - How do I solve these? 1) 2sinxcosx-cosx=0 2) cos^2(x)-0.5cosx=0 3...

TRIG! - Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6...

another precal - i have two questions for you to check please! 6cos^2x+5cosx-4=0...