Posted by **Kate** on Monday, April 16, 2007 at 7:38pm.

Compute inverse functions to four significant digits.

cos^2x=3-5cosx

rewrite it as..

cos^2x + 5cosx -3=0

now you have a quadratic, solve for cos x using the equation

cosx=(-5 -+ sqrt (25 +12)/2

## Answer This Question

## Related Questions

- trig question - Compute inverse functions to four significant digits. cos^2x=3-...
- trig - it says solve for all real solutions, compute inverse functions to 4 ...
- Math - Solving for Trig Equations - Solve the following equation for 0 less than...
- Trigonometry - Write equivalent equations in the form of inverse functions for a...
- Trig - prove the identity (sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= ...
- Trigonometry - How do I solve these? 1) 2sinxcosx-cosx=0 2) cos^2(x)-0.5cosx=0 3...
- Calc II - For the following question, we need to find the length of the polar ...
- calculus - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x...
- Calc. - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x ln...
- Math - Solving Trig Equations - What am I doing wrong? Equation: sin2x = 2cos2x ...

More Related Questions