Posted by
**JP** on
.

The equilibrium constant Kc equals 5.90 for the reaction

CH3COOH + C2H5OH <==> CH3COOC2H5 + H2O

Find the molar concentrations of acetic acid, ethanol, ethyl acetate, and water at equilibrium when .10 M acetic acid and .20 M ethanol are allowed to equilibrate.

I started like this:

I assumed 1 L of solution so I had

.10 mol CH3COOH

.20 mol C2H5OH

and in terms of moles at equilibrium...

CH3COOH= a - x

C2H5OH= b - x

CH3COOC2H5= c + x

H2O= d + x

where a, b, c, and d = moles initially, and x= moles lost

But I'm not really sure where to go from here. Any help would be much appreciated.