Posted by DANIELLE on Monday, April 16, 2007 at 2:35pm.
CAN SOMEONE PLEASE CHECK TO SEE IF I HAVE DONE THESE CORRECTLY. Thanks for your help.
Solve by completing the square
X^2-6x + (-6/2) ^2=16+ (-6/2) ^2
X-6/2= +or - 10/2
X=6 + or - 10/2
X^2-3/2x +(-3/2)^2 =-1/2+(-3/2)^2
X+3/2=+ or - sqrt7/4
X=-3 + or – sqrt 7/2
X= -3+sqrt7/2 , x=-3-sqrt7/2
Put the values in the letters and see if you get the right answer
Put the value for your first answer as
-4 squared - 6(8) = 16
See if it works in this way
No1 in line 4
why don't your reduce 6/2 to 3
line 4 would read (x-3)^2 = 25
then x-3 = +/- √25
x-3 = +/- 5
then x=8 or x = -2
no 2 you have to take 1/2 of 3/2 which would be 3/4.
then 3/4 squared is 9/16
so line 4 should read
x^2 - (3/2)x + 9/16 = -1/2 + 9/16
(x-3/4)^2 = 1/16
x=1 or x=1/2
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