# ALGEBRA 1

posted by
**DANIELLE** on
.

CAN SOMEONE PLEASE CHECK TO SEE IF I HAVE DONE THESE CORRECTLY. Thanks for your help.

Solve by completing the square

1. X^2-6x=16

X^2-6x + (-6/2) ^2=16+ (-6/2) ^2

X^2-6x+36/4= 16+36/4

(X-6/2)=100/4

X-6/2= +or - 10/2

X=6 + or - 10/2

X=-4, X=8

2. 2x^2-3x+1

2x^2-3x=-1

X^2-3/2x=-1/2

X^2-3/2x +(-3/2)^2 =-1/2+(-3/2)^2

X^2-3/2+9/4 =-1/2+9/4

X+3/2=7/4

X+3/2=+ or - sqrt7/4

X=-3 + or – sqrt 7/2

X= -3+sqrt7/2 , x=-3-sqrt7/2

Put the values in the letters and see if you get the right answer

For example

Put the value for your first answer as

-4 squared - 6(8) = 16

See if it works in this way

No1 in line 4

why don't your reduce 6/2 to 3

line 4 would read (x-3)^2 = 25

then x-3 = +/- √25

x-3 = +/- 5

then x=8 or x = -2

no 2 you have to take 1/2 of 3/2 which would be 3/4.

then 3/4 squared is 9/16

so line 4 should read

x^2 - (3/2)x + 9/16 = -1/2 + 9/16

.

.

.

(x-3/4)^2 = 1/16

..

x=1 or x=1/2