Posted by **jimmy** on Monday, April 16, 2007 at 9:59am.

The following Summation

1 2 1 2 1 2

------ x - + ------ x - + ------ x -

1+(2/n) n 1+(4/n) n 1+(6/n) n

is a right Riemann sum for this integral

f(x)dx With subintervals [1,3]

can someone help me solve for the inegrand which is f(x).?

## Answer this Question

## Related Questions

- Calculus - The following sum [(sqrt(36-((6/n)^2))).(6/n)] + [(sqrt(36-((12/n)^2...
- Calculus - The following sum [(sqrt(36-((6/n)^2))).(6/n)] + [(sqrt(36-((12/n)^2...
- Calc 2 - Can you give me the step by step instructions on how to do this problem...
- Maths - The following sum [(sqrt(36-((6/n)^2))).(6/n)] + [(sqrt(36-((12/n)^2...
- Math - The following sum [(sqrt(36-((6/n)^2))).(6/n)] + [(sqrt(36-((12/n)^2))).(...
- calculus - consider the function f(x)= x^2/4 -6 Rn is the Riemann sum where the ...
- Math! - Consider the integral from 3 to 6 S(2x^2+4x+3)dx (a) Find the Riemann ...
- calculua - consider the integral (4x^2+2x+4)dx from 0 to 6 Find the Riemann sum ...
- math, calculus 2 - Consider the function f(x)=-((x^2)/2)-9. In this problem you...
- calc help - consider the function f(x)= x^2/4 -6 Rn is the Riemann sum where the...

More Related Questions