A gas takes up a volume of 17 liters, has a pressure of 2.3 atm, and a temperature of 299K. If I raise the temperature to 350K and lower the pressure to 1.5 atm, what is the new volume of the gas?

Use the combined gas law here. I will be happy to critique your work.

(2.3 * 17) * 350 = 13685

299 * 1.5 = 448.5
13685 / 448.5 = 30.5
v2 = 30.5L

A gas takes up a volume of 22 liters, has a pressure of 4.8 atm. If I lower the pressure to 0.9 atm, what is the new volume of the gas? *

To find the new volume of the gas, we can use the combined gas law equation:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where:
P1 = initial pressure of the gas
V1 = initial volume of the gas
T1 = initial temperature of the gas
P2 = final pressure of the gas
V2 = final volume of the gas
T2 = final temperature of the gas

Let's plug in the given values:

P1 = 2.3 atm
V1 = 17 L
T1 = 299 K
P2 = 1.5 atm
T2 = 350 K

Now, we can rearrange the equation to solve for V2:

V2 = (P1 * V1 * T2) / (P2 * T1)

Substituting the values into the equation:

V2 = (2.3 atm * 17 L * 350 K) / (1.5 atm * 299 K)

Now we can calculate the new volume:

V2 = 1401.67 L / 448.5

V2 ≈ 3.12 L

Therefore, the new volume of the gas is approximately 3.12 liters.

2.5

v2=p1v1t2

p2t1

v2=(2.3atm)(17L)(300K)
(1.5atm)(299K)

v2=11,730
448.5
v2=26.16