Posted by **Anonymous** on Sunday, April 15, 2007 at 4:35pm.

the average number of pushups a United States Marine does daily is 300, with a standard deviation of 50. A random sample of 36 marines is selected. What is the probability that the sample mean is at most 320 push-ups?

With a mean of 300, you are looking for a sample using a Standard Error of the Mean (SE). (The SE functions the exact same way for a distribution of means as the SD does for a distribution of raw scores.)

SE = SD/(sq.rt.of N) = 50/6

Once you can determine how many SE above the mean the value of 320 is, use the "Area Under the Normal Distribution" table in the back of your statistics book to find the probability.

I hope this helps. Thanks for asking.

## Answer This Question

## Related Questions

- stat. - The average age of a vehicle registered in the United States is 8 years...
- statistics - A specific study found that the average number of doctor visits per...
- statistics - A specific study found that the average number of doctor visits per...
- statistics - The scores of students on the ACT college entrance examination in ...
- gre math prob of a sample - sample standard deviation = 3 sample mean = 68 n=30 ...
- Statistics - The average age of vehicles registered in the united states is 96 ...
- statistics - The average temperature in households is 67.6 degrees F. The ...
- statistics - The average age of a vehicle registered in the United States is 8 ...
- Stats. - The average age of a vehicle registered in the United States is 8 years...
- Statistics - Daily water intake (including water used in drinks such as coffee...

More Related Questions