Posted by **Anonymous** on Sunday, April 15, 2007 at 4:35pm.

the average number of pushups a United States Marine does daily is 300, with a standard deviation of 50. A random sample of 36 marines is selected. What is the probability that the sample mean is at most 320 push-ups?

With a mean of 300, you are looking for a sample using a Standard Error of the Mean (SE). (The SE functions the exact same way for a distribution of means as the SD does for a distribution of raw scores.)

SE = SD/(sq.rt.of N) = 50/6

Once you can determine how many SE above the mean the value of 320 is, use the "Area Under the Normal Distribution" table in the back of your statistics book to find the probability.

I hope this helps. Thanks for asking.

## Answer This Question

## Related Questions

- statistics - A specific study found that the average number of doctor visits per...
- statistics - A specific study found that the average number of doctor visits per...
- stat. - The average age of a vehicle registered in the United States is 8 years...
- statistics - The scores of students on the ACT college entrance examination in ...
- gre math prob of a sample - sample standard deviation = 3 sample mean = 68 n=30 ...
- Statisics - I need help on this question i am confused. I don't think the ...
- Stats 330- HELP - I need some help on this question it has two parts but i can'...
- Statistics - Daily water intake (including water used in drinks such as coffee...
- statistics - In a certain region, the mean annual salary for plumbers is $51,000...
- Statistics - he Oil Price Information Center reports the mean price per gallon ...

More Related Questions