posted by Angel on .
Nick throws a baseball upward with an initial velocity of 60 feet per second. What is the maximum height of the ball after Nick releases the ball?
Formula for the problem - h(t)=v0t-16t^2, h(t)= the height of an object in feet, v0=an object's initial velocity in feet per second, and t= time in seconds
but you know the initial velocity
so h(t) = 60t - 16t^2
If you are studying calculus, differentiate, set the derivative equal to zero and solve for t
Substitute the t value back in your equation.
If you don't know Calculus, use the method of completing the square, I hope you know what i mean by that.
I don't know what you mean by that