Saturday

April 18, 2015

April 18, 2015

Posted by **Angel** on Saturday, April 14, 2007 at 9:20pm.

Nick throws a baseball upward with an initial velocity of 60 feet per second. What is the maximum height of the ball after Nick releases the ball?

Formula for the problem - h(t)=v0t-16t^2, h(t)= the height of an object in feet, v0=an object's initial velocity in feet per second, and t= time in seconds

but you know the initial velocity

so h(t) = 60t - 16t^2

If you are studying calculus, differentiate, set the derivative equal to zero and solve for t

Substitute the t value back in your equation.

If you don't know Calculus, use the method of completing the square, I hope you know what i mean by that.

I don't know what you mean by that

**Answer this Question**

**Related Questions**

calculus - A baseball pitcher throws a baseball with an initial velocity of 133 ...

math - a baseball is hit with an initial velocity of 75 feet per second from the...

Alg 1 - A baseball player hit a ball with an upward velocity of 46 ft/s. Its ...

algebra - A baseball player releases a baseball at the height of 7 feet above ...

Algebra - A baseball player hits a baseball into the air with an initial ...

ap calculus - The height s of a ball, in feet, thrown with an initial velocity ...

Algebra - word problem - A red ball and a green ball are simultaneously tossed ...

Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...

Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...

Math - If a baseball is projected upward from ground level with an initial ...