Tuesday

July 29, 2014

July 29, 2014

Posted by **Angel** on Saturday, April 14, 2007 at 9:20pm.

Nick throws a baseball upward with an initial velocity of 60 feet per second. What is the maximum height of the ball after Nick releases the ball?

Formula for the problem - h(t)=v0t-16t^2, h(t)= the height of an object in feet, v0=an object's initial velocity in feet per second, and t= time in seconds

but you know the initial velocity

so h(t) = 60t - 16t^2

If you are studying calculus, differentiate, set the derivative equal to zero and solve for t

Substitute the t value back in your equation.

If you don't know Calculus, use the method of completing the square, I hope you know what i mean by that.

I don't know what you mean by that

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