Friday

January 30, 2015

January 30, 2015

Posted by **Sammy** on Saturday, April 14, 2007 at 2:18pm.

dx/dt= 6t^2-24t-30

dy/dt= 2t-4

dy/dx= (t-2)/(3t^2-12t-15)

Now, if dy/dx= inf, then

3t^2-12t-15=0 or

(t-5)(t+1)=0 check that.

solve for t. Put that value of t in the original equations to get x,y for the point where the tangent is vertical.

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