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December 22, 2014

December 22, 2014

Posted by **Ashley** on Saturday, April 14, 2007 at 1:57pm.

tanx(cos2x) = sin2x - tanx

Left Side = (sinx/cosx)(2cos^2 x -1)

=sinx(2cos^2 x - 1)/cosx

Right Side = 2sinx cosx - sinx/cosx

=(2sinxcos^2 x - sinx)/cosx

=sinx(2cos^2 x -1)/cosx

= L.S.

Q.E.D.

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