Sunday
May 19, 2013

Homework Help: Calculus

Posted by Kelly on Saturday, April 14, 2007 at 12:59pm.

find the equation for an ellipse that satisfies the following condition
Vertices at (-3,1) and (9,1)
one focus at (7,1)

I will assume you know the general equation of an ellipse and its properties in terms of a,b and c.

the centre would be the midpoint of (-3,1) and (9,1) which is (3,1) from which we can easily see that a = 6
one focal point is (7,1) so the distance from the centre to the focal point is 4
therefore c=4

now in a horizontally placed ellipse
b^2 + c^2 = a^2
.
.
.
.

Your equation should be

(x-3)^2/ 36 + (y-1)^2 /48 = 1

No one has answered this question yet.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Algebra 2 - Choose the equation that best represents an ellipse for the given ...
pre cal - What is the center of the conic whose equation is x^2 + 2y^2 - 6x + ...
Geometry - For an ellipse, one focus is (0,0), one vertex is (2,0), and the ...
math - how do i write this equation... ellipse with the vertices of (6,3) and (6...
precal help - Find a Parabola with Vertex (3,1) Focus (4,1) Find the vertex of ...
PRECAL - Find a Parabola with Vertex (3,1) Focus (4,1) Find the vertex of 4y^2+...
Math/Conics - Find the center, vertices, and foci of the ellipse with the ...
Pre-calculus - For the ellipse with equation 5x^2+64y^2+30x+128y-211=0, find the...
Pre-Calculus - Find the equation of the hyperbola whose vertices are at (-1,-5) ...
math - For the following problem we are asked to find an equation for the conic ...

For Further Reading

Search
Members
Community