A stone was dropped off a cliff and hit the ground with a speed of 160 ft/s. What is the height of the cliff?
Take the free fall acceleration to be 32ft/s^2
h= _______ft?
vfinal^2= 2gh you are given g, and vfinal.
A stone was dropped off a cliff and hit the ground with a speed of 160 ft/s. What is the height of the cliff?
Take the free fall acceleration to be 32ft/s^2
From Vf^2 = Vo^2 + 2gh,
160^2 = 0 + 2(32)h ---> h = 20 feet.
400
To find the height of the cliff, we can use the equation Vf^2 = Vo^2 + 2gh, where Vf is the final velocity (160 ft/s), Vo is the initial velocity (0 ft/s as it was dropped), g is the acceleration due to gravity (32 ft/s^2), and h is the height of the cliff (what we're trying to find).
Rearranging the equation, we have:
160^2 = 0 + 2(32)h
Simplifying further:
25600 = 64h
Dividing both sides by 64:
h = 400 ft
Therefore, the height of the cliff is 400 feet.