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January 29, 2015

January 29, 2015

Posted by **Mary** on Saturday, April 14, 2007 at 2:09am.

The length of the brass rod is 2.0m

The lenght of the aluminum rod is 1.0m

The coefficient of linear expansion of Brass = 19 x 10^-6

The coefficient of linear expansion of Aluminum = 23 x 10^-6.

I am unsure where to go from here.

gap= deltaL for alum + delta L for Brass

solve for delta T, it is the same in both linear expansions.

Ao do we have to add the specific heat capacities ?

Ao do we have to add the specific heat capacities ?

- Physics HELP!!!!!!!! -
**JP**, Tuesday, November 4, 2008 at 7:08pm2E-3= (19E-6)(2)(DeltaT) + (23E-6)(1)(DeltaT)

Simplified equation:

.002= (3.8E-5) (DeltaT) + (2.3E-5) (DeltaT)

More simpllified:

.002= (6.1E-5) (DeltaT)

DeltaT= 32.7869

Answer:

32.7869 + 29 = 61.7869

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