Saturday

October 25, 2014

October 25, 2014

Posted by **david** on Friday, April 13, 2007 at 11:07pm.

what i did so far:

F(x)=kx

10=k4

k=5/2

by hooke's law i need to find the integral of 5/2x right. but what are the bounds.

All you have to do is use the formula

Work = potential energy increase = (1/2) k x^2, where k is the spring constant that you computed (which is 2.5 lb/inch) and x = 6 inches.

The answer wil be in inch-lb. If you want it in foor-lb, you will have to divide by 12.

You could also do it by integration

Work - Integral of F dx = Integral of kx dx from x=0 to x=6. The answer is the same.

- work force -
**carlos Martinez**, Tuesday, September 13, 2011 at 5:19pm15/4...... (1/2)(2.5)(6^2)=45 in/lb converto to feet divide by 12... 15/4

**Answer this Question**

**Related Questions**

Physics - If the work required to stretch a spring 4 feet beyond its natural ...

Math 207 - If the work required to stretch a spring 4 feet beyond its natural ...

Sorry, another math problem please - Hooke's Law asserts that the force required...

Physics - Hooke's law states that it takes a force equal to kΔx is required...

Calculus/Physics - A spring has a natural length of 10in. An 800lb force ...

calculus - a spring exerts a force of 150 N when it is stretched 0.4 m beyond ...

Calculus - if the work required to stretch a spring 1 ft beyond its natural ...

Math-Hooke's law - Using Hooke's Law (F=kx) determine: A) A weight of 5 pounds ...

Calculus - If the work required to stretch a spring 1 ft beyond its natural ...

calculus/physics - A force of 10 pounds stretches a spring 2 inches. Find the ...