Posted by **Febby** on Friday, April 13, 2007 at 9:12am.

A particle is put inside an accelerator at time t=0. After t sec, its velocity is 10^5t^2 m/s. How far does the particle move during the first 10**-2 sec?

distance= int velocity dt

= INT 1E5 t^2 dt

limits 0 to 1E-2 sec

## Answer This Question

## Related Questions

- physics help - The magnitude of the velocity of a particle which starts from ...
- physics help - The magnitude of the velocity of a particle which starts from ...
- Calculus - I don't understand what the graph is suppose to show and what the ...
- Calculus - Solve: The posistion of a particle moving along a coordinate line is ...
- Math/ Calculus Please HELP!!! - The following table gives the velocity v(t) (in ...
- calculus - a particle moves along a number line measured in cm so that its ...
- physics - A particle leaves the origin with an initial velocity = (2.35 m/s) and...
- physics - a particle covers 1/2 distance between A and B with a velocity V0. ...
- calculus - 5. A particle moves along the y – axis with velocity given by v(t)=...
- Physics - A particle leaves the origin with an initial velocity of 4.90 m/s in ...

More Related Questions