# alg2

posted by
**sara**
.

how would you set this problem up using pascal's triangle?

(x+y)5 (raised to the 5th power)

5th row, 6 terms.

http://en.wikipedia.org/wiki/Pascal's_triangle

1

1 1

1 2 1

1 3 3 1

1 4 6 4 1

1 5 10 10 5 1

1 6 15 20 15 6 1

so (x+y)^5

= x^5 + 5x^4y + 10x^3y^2 + .... + y^5