Posted by **jasort20** on Wednesday, April 11, 2007 at 4:43pm.

This is what the directions state to do:

(A) Complete the table,(B)describe the resulting graphs by identifying the vertex point, (c) the graph’s direction, (d) and any axis intercepts gleaned from the table or graph.

Problem #1

Equation is : y = -x + 1

so These are my answers:

(A) Table : (i am going to give it in corrdinate points)

(-1 , 2 )

(0,1)

(1,0)

(B) There is no vertex & no axis of symmetry.

(C) The direction fo line is increasing on the left and decreasing on the right.

(D) Axis of intercepts are : (0,1) and (1,0)

Problem #2 (same directions as one)

Equation: y =x^2 -4x

A)Table:

(-1 , 5 )

(0,0)

(1,-3)

(2,-4)

(3,-3)

(4,0)

(5,5)

(B)Vertex (2,-4)

axis of symmetry x = 2

(c) The direction of the parabola opens upward because the coefficient has a positive x^2.

(d) Axis intercepts are : (0,0) and (4,0)

all correct.

thank you bobpursley

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