Monday

September 1, 2014

September 1, 2014

Posted by **Nikki** on Tuesday, April 10, 2007 at 11:57pm.

1. I'm asked to find a cartesian equation for the polar graph of this polar equation: r^2 = sin(2(theta))

The answer I got was

(x^2+y^2)^2/(2xy) = 2

Is this the correct way to express it?

2. I need to find the cartesian equation for this parametric equation:

x = sec(t) + tan(t)

y = sec(t) - tan(t)

I have tried using the identity tan^2x + 1 = sec^2x, but I feel like I'm moving in circles!

I'd appreciate it so much if someone could help me!!! Thanks =)

2. x + y = 2 sec t

x - y = 2 tan t

(1/4)(x+y)^2 = (1/4)(x-y)^2 + 1

This gets rid of the t terms. Rearrange and simplify.

**Answer this Question**

**Related Questions**

Pre-Calculus - Please check: 1.Find polar equation of x^2 + y^2 = 10y r^2 for x^...

Pre-calculus; urgent ! Please help ! - 1.Graph the polar equation r=3-2sin(theta...

Calculus please help ! - 1.Graph the polar equation r=3-2sin(theta) 2. Find the ...

Math ! Please Help ! - 1.Graph the polar equation r=3-2sin(theta) 2. Find the ...

calculus - for what value of r=4sinč have vertical tangent? In polar coordinates...

Calc 2 - Find a Cartesian equation for the polar curve y = 5tan(theta)sec(theta...

Math (Calculus) - Given any Cartesian coordinates, (x,y), there are polar ...

math - change equations to polar form: 1) y= -1 2) x^2 + y^2 = 4 how would i do ...

Calculus - I wanted to confirm that I solved these problems correctly (we had to...

Polar Equations - Identify each polar equation by changing the equation to ...