Posted by **Chris** on Tuesday, April 10, 2007 at 9:23pm.

The rate of performance is given by dN/dt=1/(2sqroot(t+1)) where N is the number of unity completed t hours after beginning a new tak.

If 2 units are completed afer 3 hours, how many units are completed after 8 hours?

N= INT 1/2 (t+1)^(-1/2)

I will be happy to critique your thinking. Solve for the constant of integration, and you have it.

I really don't understand the problem for some reason, but my thinking thus far is INT(t+1)^(-1/2)

1/2 INTu^(-1/2)du

1/2((u^(1/2)/(1/2))du

u^(1/2)du

(t+1)^(1/2)

Anything you can do to help would be great!

That is it. YOu can check it by taking the derivative. DO NOT forget the constant of integration, I think you need it.

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