Sunday

March 29, 2015

March 29, 2015

Posted by **Manny** on Tuesday, April 10, 2007 at 3:57pm.

Calculate the ratio of the escape velocities from the moon and Earth

In order to escape the gravitaional pull exerted by a central body on an orbiting object, it must must achieve a minimum inertial velocity relative to the central body. This velocity is called the escape velocity. You can determine the minimal escape velocity required to escape from any planet yourself. Escape velocity from a planet is given by Ve = sqrt[2µ/r] where Ve = escape velocity in feet per second, µ = the planet's gravitational constant, ft.^3/sec.^2 (equal to GM where G = the Universal Gravitational Constant and M = the mass of the planet), and r = the radial distance from the center of the planet in feet. For the earth, µ = 1.407974x10^16 and r = 3963 miles = 20,924,640 ft. so the general escape velocity, direct from the surface, would be Ve = sqrt[2(1.407974x10^16)]/20,924,640 = ~36,685 ft./sec. = ~25,007 mph.

The same calculation can be made for the moon using µ = 1.731837x10^14.

Divide the two and you will have your ratio.

**Answer this Question**

**Related Questions**

math - 5.Escape velocity is the speed necessary to escape the gravitational pull...

chemistryyy - The escape velocity of planet earth is 11.2 km/s. At what ...

physics - calculate the escape velocity for the following; assume a launch from ...

Physics - Suppose that the ratio of the Moon's mass to the Earth's mass is given...

physics - Calculate the magnitudes of the gravitational forces exerted on the ...

physics - In the Earth–Moon system, there is a point where the gravitational ...

Physics - Take into account the Earth's rotational speed (1 rev/day) and use 5 ...

Physics - A distant planet has a mass of 0.6400 ME and a radius of 0.9000 RE. ...

Physics - A distant planet has a mass of 0.6400 ME and a radius of 0.9000 RE. ...

Physics - The earth has about 80 times the mass of the earth’s moon. The ...