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when Br2 (5.7mol) and Cl2 (.0934mol/L)in a 61 L vessel at 604'C are allowed to come to equlibrium the mixture contains .0523 mol/L of BrCl. What concentration of Cl2 is reacted?

- i know how to find the Kc...

Br2 + Cl2 ==> 2BrCl
0.0523 mol/L BrCl at equilibrium in a 61 L vessel = 0.0523 mol/L x 61 L = mols BrCl formed at equilibrium.
1/2 x mols BrCl = mols Cl2 reacted.
Check my thinking.

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