Posted by **gobind** on Sunday, April 8, 2007 at 12:48pm.

An asteroid, whose mass is 2.0 10-4 times the mass of Earth, revolves in a circular orbit around the Sun at a distance that is 2.9 times Earth's distance from the Sun.

(a) Calculate the period of revolution of the asteroid in years.

(b) What is the ratio of the kinetic energy of the asteroid to the kinetic energy of Earth (Kasteroid / KEarth)?

Wouldn't Keplers laws handle this nicely? You know the period for Earth, the radii for each.

## Answer This Question

## Related Questions

- physics - An asteroid, whose mass is 2.0 10-4 times the mass of Earth, revolves ...
- Physics - What is the orbital velocity of the Earth around the Sun, assuming the...
- physics - The mean distance of the planet Neptune from the Sun is 30.05 times ...
- Physics - The period of the earth around the sun is 1 year and its distance is ...
- mit - A spacecraft of mass m is first brought into an orbit around the earth. ...
- earth - planet is in circular orbit around the Sun. Its distance from the Sun ...
- Physics - How would the speed of Earth’s orbit around the sun change if Earth’s ...
- physics - calculate the centripetal acceleration of the earth in its orbit ...
- Physics - Given that the Sun has a mass 333,000 times larger than Earth’s mass ...
- REALLY EASY - Which of the following explanations correctly describes the reason...

More Related Questions