Find the sum of the seix even multiples of 18 starting from 36
six*
Sum= 18 (2 + 4 + 6 + 8 + 10 + 12)=
=18*2(1 +2 + 3 + 4 + 5 + 6)
=36(21)= 36*20 + 36
= 720 + 36= 756
check my math.
To find the sum of the six even multiples of 18 starting from 36, you first need to find the pattern of these even multiples. Since 18 is already an even number, you can simply multiply it by consecutive even numbers to get the desired multiples.
The first multiple is obtained by multiplying 18 by 2, giving you 36. The second multiple is obtained by multiplying 18 by 4, resulting in 72. Continuing this pattern, you can generate the following even multiples of 18: 36, 72, 108, 144, 180, and 216.
To find the sum of these multiples, you add them together: 36 + 72 + 108 + 144 + 180 + 216 = 756.
Your calculation is correct, and the sum of the six even multiples of 18 starting from 36 is indeed 756.