Posted by **CJ** on Saturday, April 7, 2007 at 4:57pm.

A water bed has dimensions of 1.83mx1.86mx.238m. The floor of the bed room will tolerate an additional weight of no more than 6660N. Find the weight of the water in the bed and determine whether it should be purchased.

The weight of the water in the water bed is (volume* g* density of water)

= 810 m^3* 9.8 m/s^2 * 1000 m/m^3 = 9.61*10^3 N

That is more weight than the floor can support.

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