Posted by
**Mary** on
.

I'm sorry bobpursley I don't understand your response, please clarify.

When an object of mass m1 is hung on a vertical spring and set into vertical simple harmonic motion, its frequency is 12 Hz. When another object of mass m2 is hung on the spring along with m1, the frequency of the motion is 4 Hz. Find the ratio m2/m1 of the masses.

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Physics HELP!!!!!!!! - bobpursley, Wednesday, April 4, 2007 at 9:12pm

w= sqrt (k/m)

w^2= k/m

(w1/w2)^2=9 = (m1+m2)/m1

9= 1 + m2/m1

check my thinking.

What is it you do not understand?

Algebra leads you to m2/m1= 8

Post the question in which you do not understand.

hi