Posted by **Amy** on Thursday, April 5, 2007 at 6:02pm.

show that the curves r=asin(è) and r=acos(è) intersect at right angles.

can you show that the derivatives for each are the negative reciprocal of each other? That is the key.

i need more info..i know how to find the derivative...but how will that prove my question. Do I need to graph it after i find the derivatives?

The definition of perpendicular lines is that their slope is the negative reciprocal. The deravative is the slope.

You will need to determine the point of intersection, then evaluate the derivatives at that point. If one is the negative reciprocal of the other, then by definition, they are perpendicular.

## Answer this Question

## Related Questions

- Calculus - Show that the curves r=acos(è) and r=cos(è) intersect at right angles...
- calculus - Show that the curves (y= √2sinx) and (y=√2cosx) intersect...
- calculus - two curves are orthogonal at a point of intersection of their ...
- calculus - Find all values of 'a' such that y=a/(x−9) and y=x^2−18x+...
- Calculus - dy/dx= (y^2 -1)/x 1. Give the general equation of the curves that ...
- Calculus-check my answers please - dy/dx= (y^2 -1)/x 1. Give the general ...
- Calculus Help - Let c and dd be positive real numbers. Show that regardless of c...
- CALCULUS ONE! - The graph of sinx and cosx intersect once between 0 and pi/2. ...
- Geometry - 2.Given two segments with lengths x and y (x does not equal y), which...
- calculus - 1.) values of f(t) are given in the following table: t 0 2 4 6 8 10 f...