Posted by **Paul** on Tuesday, April 3, 2007 at 4:33pm.

A non-uniform beam of length L and weight w makes an angle of è with the horizontal. It is held in position by a frictionless pivot at its upper-right end and by a cable a distance of farther down the beam and perpendicular to it. The center of gravity of the beam is a distance of x down the beam from the pivot. Lighting equipment exerts a downward force of F on the lower-left end of the beam.

a)Find the tension T in the cable.

b)Find the vertical component of the force exerted on the beam by the pivot.

Your answer should be positive if the force is upward, negative if the force is downward.

c)Find the magnitude of the horizontal component of the force exerted on the beam by the pivot.

Your answer should be positive if the force is rightward, negative if the force is leftward.

I don't even know where to start?

I don't follow the picture. However, you can sum moments about any point, and you can sum vertical and horizontal forces since it is in equilibrium. That will give the governing equations.

- Physics -
**Anonymous**, Sunday, April 11, 2010 at 3:30pm
I don't know either

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