Monday

July 28, 2014

July 28, 2014

Posted by **Blake** on Monday, April 2, 2007 at 1:29pm.

12x^2+y^2+6x-9=0

not sure what you mean by "solve this conic"

You want to know what kind of conic? ellipse

to find out its properties you have to change it into standard form (x-h)^2/a^2 + (y-k)^2/b^2 = 1

I would first divide by 12

x^2 + y^2/12 + x/2 = 9/12

complete the square for the x terms, adding the same quantity to both sides

x^2 + x/2 + 1/16 + y^2/12 = 3/4 + 1/16

(X + 1/4)^2 + Y^2/12 = 13/16

Divide each term by 13/16

(x + 1/4)^2/(13/16) + y^2/(26/16) = 1

so we have an ellipse with centre at (-1/4,0), with a = √13 /4 and b = √26 / 4

**Related Questions**

Conic section identification - Explain which conic section this equation and ...

algebra - A conic section has the equation x^2+y^2+12x+8y=48. Determine the ...

pre cal - What is the center of the conic whose equation is x^2 + 2y^2 - 6x + ...

Conic Sections - How do you find the equation for this problem? Conic Center(1,3...

Math - solve for the conic in the equation y^2-6y+12x+33=0

Conic Sections - What place or object in Washington D.C. looks like a conic ...

Algebra 2 - Conic Sections - I'm unsure of how to do this. Walk me through it? ...

algebra 2 - Determine values for A, B, and C such that the equation below ...

algebra 2 - Determine values for A, B, and C such that the equation below ...

Algebra II - I am lost on this one!!! Determine values for A, B, and C such that...