A bottle of wine contains 13.1% ethanol by volume. The density of ethanol (C2H5OH) is 0.789 g/cm3. Calculate the concentration of ethanol in wine in terms of mass percent and molality.

i don't know how to get molality. please help!!!!

Molality is the number of moles of solute divided by the mass of solvent.

This is solvent NOT solution.

Is this OK?

dfdsf

75

all you gotta do is.... walk awayyyyy

I apologize for the confusion. Molality is indeed the number of moles of solute divided by the mass of solvent, not solution. Thank you for pointing that out.

To calculate the concentration of ethanol in wine in terms of molality, you will need to know the volume of wine (solvent) and the amount of ethanol present (solute).

First, let's convert the density of ethanol (0.789 g/cm3) to kg/L to match the units of molality:

Density of ethanol = 0.789 g/cm3
= 0.789 kg/L

Next, calculate the mass of ethanol in the wine:
Mass of ethanol = Volume of wine (L) × Density of ethanol (kg/L)
= Volume of wine (L) × 0.789 kg/L

Since the wine contains 13.1% ethanol by volume, we can determine the exact volume of ethanol in the wine by multiplying the volume of wine by 13.1% (0.131):
Volume of ethanol = Volume of wine (L) × 0.131

Now, we can calculate the molality using the formula:
Molality (m) = Moles of solute / Mass of solvent (kg)

To calculate the moles of ethanol, we can divide the mass of ethanol by its molar mass. The molar mass of ethanol (C2H5OH) is approximately 46.07 g/mol.

Moles of ethanol = Mass of ethanol (g) / Molar mass of ethanol (g/mol)

Finally, we can substitute these values into the molality formula to find the concentration of ethanol in wine in terms of molality.