Posted by **Cavin** on Saturday, March 31, 2007 at 2:25pm.

A pendulum clock can be approximated as a simple pendulum of length 1.20m and keeps accurate time at a location where G=9.83m/s2. In a location where g=9.73m/s2, what must be the new length of the pendulum, such that the clock continues to keep accurate time9 that is, its period remains the same)?

Isnt Period on a pendulum clock equal to

2PI sqrt (length/g) ?

so if the period are the same, setting them equal

2PI sqrt (1.2/8.83) = 2PI sqrt (length/9.73)

solve for length.

## Answer This Question

## Related Questions

- Physics - A pendulum clock can be approximated as a simple pendulum of length 1....
- physics - A pendulum clock was moved from a location where g=9.8152 m/s^2 to ...
- Algebra II - The number of oscillations made by a pendulum in a given time is ...
- Algebra II - The number of oscillations made by a pendulum in a given time is ...
- Calculus application of sin function - a horizontal position of the pendulum of...
- programming - Application: Pendulum Clocks Pendulums used in clocks, such as ...
- physics - A clock has a copper pendulum with a period of 1.000 s at 17.3°C. ...
- physics - A pendulum clock has a pendulum shaft made of aluminum which has a ...
- physics - A clock has an aluminum pendulum with a period of 1.000 s at 20.2 °C. ...
- physics - A clock has an aluminum pendulum with a period of 1.000 s at 20.3 °C. ...

More Related Questions