Homework Help: physics

Posted by Cavin on Saturday, March 31, 2007 at 2:25pm.

A pendulum clock can be approximated as a simple pendulum of length 1.20m and keeps accurate time at a location where G=9.83m/s2. In a location where g=9.73m/s2, what must be the new length of the pendulum, such that the clock continues to keep accurate time9 that is, its period remains the same)?

Isnt Period on a pendulum clock equal to

2PI sqrt (length/g) ?

so if the period are the same, setting them equal

2PI sqrt (1.2/8.83) = 2PI sqrt (length/9.73)

solve for length.

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