Posted by **COFFEE** on Friday, March 30, 2007 at 4:25am.

A 1.1 kg particle-like object moves in a plane with velocity components Vx = 30 m/s and Vy = 90 m/s as it passes through the point with (x, y) coordinates of (3.0, -4.0) m.

(a) What is its angular momentum relative to the origin at this moment?

_____ kg*m^2/s k

(b) What is its angular momentum relative to the point (-2.0, -2.0) m at this same moment?

_____ kg*m^2/s k

---------------

i drew a points on a flat xy plane.. but im not sure if i drew it correctly. i have the Vx component towards the positive X direction and the Vy towards the negative Y direction.

angular momentum = r x p

r x p = m (r x v)

......= 1.1 (r x 30)

......= 1.1r x 30

-33 = 1.1r

-30 = r

.. im stuck.. help!

1. Angular momentum= R x mV Where mV is the linear momentum, x is the cross product, and R is the position vector.

Angular momenum= m(3i-4j)x(30i+90j)

= m270k + m 120k

= m*390 k

check my thinking.

Why did you do the Vy in the negative y direction?

## Answer this Question

## Related Questions

- physics - A 1.8 kg particle-like object moves in a plane with velocity ...
- Physics - A 2.1 kg particle-like object moves in a plane with velocity ...
- Angular Momentum - 2.0 kg particle-like object moves in a plane with velocity ...
- Re: Physics - Posted by COFFEE on Friday, March 30, 2007 at 4:25am. A 1.1 kg ...
- physics - The position vector r of a particle moving in the xy plane is r=2ti+...
- Physics - At t=0 a particle starts from rest at x=0, y=0 and moves in the xy ...
- physics - Two forces, 1 = (3.85 − 2.85) N and 2 = (2.95 − 3.65) N, ...
- Physics - A 1.00 kg particle has the xy coordinates (-1.20 m, 0.500 m) and a 3....
- Physics - A 5.60-kg particle has the xy coordinates (-1.20 m, 0.500 m), and a 5....
- math - The acceleration, ams^-2, of a particle is given by a =25 – 9t^2, where t...